a^2+33a-148=0

Solution for a^2+33a-148=0 equation:

a^2+33a-148=0

a = 1; b = 33; c = -148;
Δ = b2-4ac
Δ = 332-4·1·(-148)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-41}{2*1}=\frac{-74}{2}
=-37
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+41}{2*1}=\frac{8}{2}
=4
$